Do whatever is in the brackets first
G'day All,
This is really three sums.
The way to approach it is to do whatever has to be done in the brackets first. So (1+2) = (3)...... The answer to the first sum has to stay within the brackets ... 6/2(3)=
The second sum involves the part of the question not within the brackets so it is 6/2 or 6 divided by 2 = 3
So the result at the end of the second sum is written up as 3(3)
The third sum is performed to get rid of the brackets. To do this the opposite of what function was done to get the second answer is performed on the sum. To recap - in sum 6/2 which is 6 is divided by 2 to get 3
So the opposite of divide is to multiply so to get rid of the bracket out of the equation it becomes 3 x 3 = 9
The answer is 9 - now that I have stopped reliving nightmares of NSW Year 12 maths exams I will go and curl up somewhere and hide.
OMG now I am having flashbacks about how to do quadratic equations - Noooooooo
Kind Regards
Lionel