Switch SW
Contact Block CB
Following some excitement with a melting wire from the starter to the ammeter, I’ve taken an interest in all things wire. Can anyone tell me please from the attached what SW and CB stand for with regard to the coil? Is this code for - and +? Also for the 57 88” , were indicators at the front only? Mine has indicators at the front single stop light only on passenger rear and a combined “modern” lens drivers side rear containing stop light and flasher light . All comments gratefully received as usual. Trucks not on the road so no rush.
cheers,
d
1957 88 Petrol (Chumlee)
1960 88 Petrol (Darwin)
1975 88 Diesel (Mutley)
Switch SW
Contact Block CB
1974 S3 88 Holden 186.
1971 S2A 88
1971 S2A 109 6 cyl. tray back.
1964 S2A 88 "Starfire Four" engine!
1972 S3 88 x 2
1959 S2 88 ARN 111-014
1959 S2 88 ARN 111-556
1988 Perentie 110 FFR ARN 48-728 steering now KLR PAS!
REMLR 88
1969 BSA Bantam B175
The maximum current expected to flow through the ammeter (and associated wiring) in a Series 1 is around 30A. The smallest alternator is likely to be rated at 35A, with most higher than this.
The result of this will be current beyond the design level for both the ammeter and wiring. Unless the alternator is rated at something like 60A or higher, this current will be unlikely to melt the wiring if it is in good condition - but it may not be. this sort of current, especially the sudden rush just after starting, is likely to damage the ammeter by bending the pointer.
Also, the thin wiring to and from the ammeter is going to limit the actual charge from the alternator.
The best solution is to bypass the ammeter, running a wire direct from the alternator to the battery - in this case, the ammeter will only show the discharge, and adding a voltmeter to show the battery state could be a good idea.
John
JDNSW
1986 110 County 3.9 diesel
1970 2a 109 2.25 petrol
Was also going to suggest a "shunt" to say 50%, then it is just double the displayed value.
You will need someone who can calculate the value of the resistor in parallel that you will need to achieve that result. (across the two ammeter terminals).
Cheers
RF
Search AULRO.com ONLY! |
Search All the Web! |
---|
|
|
Bookmarks