Thread: Airflow volume calculation, just for fun.

Originally Posted by Bohica

Driving with the Nanocom looking at air flow it gives the amount in grams per second. No useful. A quick calculation gives an result of 270 cm3 per second at air pressure 101kPa and 40C air temp

It's kg/HR, it's incorrectly labelled.

Quick update and we have 7.4cm3 per second or 269L per hour.

Originally Posted by Bohica

Quick update and we have 7.4cm3 per second or 269L per hour.

Is that air temp and volume going into the engine,TD5?

Is 40 degrees air into engine after the intercooler,if so what was the air temp going into the intercooler,or ambient,which should be pretty close?

Originally Posted by shack

It's kg/HR, it's incorrectly labelled.

+1 ^^^, nanocom glitch, the values are correct just the unit is wrong

Originally Posted by Bohica

Quick update and we have 7.4cm3 per second or 269L per hour.

That can't be anywhere near correct. Let's do a sanity check without taking into account volumetric efficiency or intake restrictions.

Let's say idling at 800rpm and a 2.0L displacement. That's 1L per revolution. 1L * 800 == 800L / minute or 48,000L / hour.

Without even looking at the values your figure and my figure are two orders of magnitude different.

Litres per hour doesn't really mean anything anyway, you need to know the weight...

For that you need to know the temp.

The MAF already does all that for you.

Should remember though the OP says it was just for fun.

I get that, math for fun, it's good for mental agility.

Originally Posted by scarry

Is that air temp and volume going into the engine,TD5?

Is 40 degrees air into engine after the intercooler,if so what was the air temp going into the intercooler,or ambient,which should be pretty close?

Yes. The 40C is the temp from the Nanocom. Air temp going into the intercooler would be higher than ambient. The intercooler cools it down to 40C, external temp was 23C iirc

Originally Posted by BradC

That can't be anywhere near correct. Let's do a sanity check without taking into account volumetric efficiency or intake restrictions.

Let's say idling at 800rpm and a 2.0L displacement. That's 1L per revolution. 1L * 800 == 800L / minute or 48,000L / hour.

Without even looking at the values your figure and my figure are two orders of magnitude different.

Yes the discrepancy is huge, I wonder why. Ah well, back to the spreadsheet!