How's your maths?

**barryj** · 15th October 2007, 12:25 PM

For all who ever wondered about the importance of maths at school;

Try it, it really works...........

YOUR AGE BY EATING OUT

Don't tell me your age; you probably would tell a falsehood anyway-but your waiter may know!

YOUR AGE BY DINER & RESTAURANT MATH

This is pretty neat.

DON'T CHEAT BY SCROLLING DOWN FIRST!

It takes less than a minute .

Work this out as you read ...

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat.

(more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50

5. If you have already had your birthday this year add 1757 ....

If you haven't, add 1756.

6. Now subtract the four digit year that you were born.

You should have a three digit number

The first digit of this was your original number

(i.e., how many times you want to go out to restaurants in a week.)

The next two numbers are

YOUR AGE! (Oh YES, it is!!!!!)

THIS IS THE ONLY YEAR (2007) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS

mittadisco · 15th October 2007, 12:29 PM

Yep - it worked.

**MrsMcRover** · 15th October 2007, 12:48 PM

Sure Does !

**stevo68** · 15th October 2007, 12:59 PM

Yes it does work, but how

, hurts my brain to try and work it out. Maybe Charlie from "Numbers" would know

Regards

Stevo

**sam_d** · 15th October 2007, 01:42 PM

Originally Posted by barryj

THIS IS THE ONLY YEAR (2007) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS

Well, this is true for 2007 but to work out how old you will be in 2008 just use 1758 instead of 1757 and 1757 instead of 1756 in step 5.

Worked for me! I now know how old I will be next year!

**Quarks** · 15th October 2007, 02:12 PM

How's my maths?

I get:

Let x be an integer, 1 ≤ x ≤ 9
= 50(2x + 5) + 1757 - (2007 - [age])
= 100x + 250 + 1757 - 2007 + [age]
now, 250 + 1757 = 2007
hence
= 100x + [age]

Now easily visible is that the x has been moved to the first digit by multiplying by 100, as described
and hence from this, it only holds for ages 0 ≤ [age] ≤ 99.

Yes, I worked that out instead of doing my maths assignment for uni. No, I don't think the lecturers will accept this instead!

**stevo68** · 15th October 2007, 02:20 PM

How's my maths?

I get:

Let x be an integer, 1 ≤ x ≤ 9
= 50(2x + 5) + 1757 - (2007 - [age])
= 100x + 250 + 1757 - 2007 + [age]
now, 250 + 1757 = 2007
hence
= 100x + [age]

Now easily visible is that the x has been moved to the first digit by multiplying by 100, as described
and hence from this, it only holds for ages 0 ≤ [age] ≤ 99.

Yes, I worked that out instead of doing my maths assignment for uni. No, I don't think the lecturers will accept this instead!

AARRGGGHHHHHHH, flash backs to Business Mathematics at Uni, must shake out of head, must close eyes, pretend never saw the word "integer"

Regards

Stevo

**Redback** · 15th October 2007, 02:27 PM

Yes i got my age, now what, i already knew my age from my birthday

Baz.

**Redback** · 15th October 2007, 06:00 PM

Originally Posted by Numpty's Missus

Well.....

I guess you now also know how many times you wish you could eat out every week

I knew that too, 2

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