Has anybody read Australian Four Wheel Drive Monthly, particularly Pat Callinans article on how to winch and calculate how much force is needed to extricate a bogged Forby?
What a load of rubbish!!
Read Pats "formulas" for calculating required pulls then sit back and consider a few thing I'm going to teach y'all.
Pat is right on a few things, there 
are 4 types of resistance to take into consideration.
1. Rolling Resistance, this being the resistance to motion given the surface the   vehicle is on, ie, Bitumen, Grass, Sand or Mud
2. Gradient Resistance, the effort required to overcome gravitys pull on an incline
3. Damage Factor, did you damage anything that might increase resistance tomotion, rip a tyre off a rim, bend a steering arm etc.
4. Add a safety margin.
To work out rolling resistance, take the weight of your vehicle and divide it by a. 25 for bitumen or concrete
b. 10 for gravel
c. 7 for grass
d. 5 for sand
e  2 for mud
To work out Gradient resistance,
a. calculate the slope
b. Factor 1/60th of a tonne for every degree of slope
To work out a Damage factor,
throw in 25% of the vehicles mass for every damaged wheel.
Safety Factor is 25% of the total of all of the above.
This will give you a Total Pull Required. (TPR)
Sooooooo.
 Using the example in the magazine of a 3.3 tonne GU Towning a 1 Tonne Camper trailer  Bogged to the chassis.
RR= 4.3/2= 2.15 Tonne
GR=0
DF=0
Total =2.15 Tonne
Safety Factor 2.15/4=.53 Tonne
TPR=2.68 Tonnes
A whole lot less than the 12.9 Tonne quoted!
Lets do another,
Blknight.aus has a fully loaded Big Red of around 3 Tonne stuck on a muddy slope of around 40 degrees. ( sorry Dave, hope you don't mind)
RR= 3/2 = 1.5
GR= 3000kg/60*30=1.5 (1500Kg)
DF=0
Total = 3.00
Safety Factor = 3.00/4=.75
 TPR=3.75 Tonnes
Now you know why Tirfors are so much fun

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