
Originally Posted by
uninformed
Does the X-spring and more "spring rate" to the springs already in the vehicle?
I just watched a vid, by the looks of it when the vehicle is at rest the x-spring is being compressed inside its little cup. And to me it is not idependant of the normal spring????
The rate changes depending upon the axle travel and spring extension.
If the spring rates are:Ko for the outer spring
Ki for the inner spring
Although the inner spring is inside the outer, the top hat effectively couples the springs in series, not parallel.
Once the outer spring looses direct contact with the axle during rebound/droop the combined spring rate becomes less than either of the individual rates and:Combined spring rate = (Ko x Ki) / (Ko + Ki)
While the axle is in direct contact with the outer spring the spring rate will be the rate of the outer spring, i.e. spring rate = Ko
Edit: I wrote that while having breakfast and Dougals post came up while I was taking my time typing, etc.
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