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Thread: A snorkel - kind a! Work in progress

  1. #11
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    Scrub the comment about interference between the air filter and the internal spigot of the PVC flanged pipe - I'll just cut away the internal PVC protrusion - not needed. I'd retained it, because I'd included a mossie net fitting - not needed really - or could be installed elsewhere.

    Feeling better about myself now!! Just the valve block bringing me down now.

  2. #12
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    Some more pictures - Paul you made.me look again at the exhaust manifold and the flexible hose for the snorkel. It's really not that close. Plenty of other plastic and electrical fittings in the same vicinity.
    Attached Images Attached Images

  3. #13
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    75mm is plenty! Just take a good look at the entry point from LH Gaurd or the inside dia of MAF so im sure 75mm has enough volume to handle required airflow.

  4. #14
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    Would anyone know how much air the 4.6 uses on full song? 400 litrs per minute springs to mind but not sure why...

  5. #15
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    Quote Originally Posted by benji View Post
    Would anyone know how much air the 4.6 uses on full song? 400 litrs per minute springs to mind but not sure why...
    OK, just a guess from a non engineering perspective. 4.6 litres is the capacity to be drawn per revolution, multiply the 4.6 litres by the RPM to come up with the answer? If the theory is correct, @ 6,000 rpm that's 27,600 litres per minute!

    Gary

  6. #16
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    Quote Originally Posted by mtb_gary View Post
    OK, just a guess from a non engineering perspective. 4.6 litres is the capacity to be drawn per revolution, multiply the 4.6 litres by the RPM to come up with the answer? If the theory is correct, @ 6,000 rpm that's 27,600 litres per minute!

    Gary
    Then divide by 4 because the inlet valves are only open every 4 revolutions due to being a four stroke. Well this would be maximum flow theoretically possible (friction would slow it down I'm sure) without a turbo or supercharger. Me thinks, not knows from experience.

  7. #17
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    Yeh, just a tad out with 400 then.
    I think you'd divide the number by two. Its 4 strokes but 2 revolutions.

    Your theory makes sense in my back yarders brain, though it could even be a bit higher due to inlet manifold pulses.

  8. #18
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    Which would be 6.9 cu.m. per minute, or 0.115 cu.m. per second. With cross sectional area of 3.14 x 0.05 x 0.05 = 0.00785 it means the velocity of the air flow would be 14.65m/s. Or 52.2 km/h if I've got my maths right. Seems reasonable. Obviously a smaller dia makes the flows higher - assuming no friction losses.

  9. #19
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    Quote Originally Posted by davidsonsm View Post
    Which would be 6.9 cu.m. per minute, or 0.115 cu.m. per second. With cross sectional area of 3.14 x 0.05 x 0.05 = 0.00785 it means the velocity of the air flow would be 14.65m/s. Or 52.2 km/h if I've got my maths right. Seems reasonable. Obviously a smaller dia makes the flows higher - assuming no friction losses.
    Well we got there eventually ha ha. Team work lol.

  10. #20
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    Put it this way, a 4.0 1UZ toyo will breathe to 11,000rpm through 48mm ITB's with only 70mm. Other thing's like plenum volume, laminar flow and pulse reversion need to be considered in volume calculations.

    Another example, a 4.7 UZ through 53mm ITB's with a well designed plenum at 15,000 required 2 x 100mm inlets (one per bank) but it didn't really work until the plenum was designed with a bridge so that reversions could be smoothed out. Then look out.

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